![]() ![]() The R1-R3 link needs the neighbor command for the adjacency to stay upī. Which of the following statements is true about the serial links that terminate in R3?Ī. In my exam, there was some little change in ospf evaluation, I mentioning below the question with changed answer: Regarding to sims, you should be careful because you might find that there some minor changes in the sims (like ip addess, subnets, ospf process numbers, eigrp autonomous number and so on) so check with show run command if that possible before starting the configuration, don’t not rush to configure blindly. Most the question came from the 41q tagwa, so you have to study it very well,īUT it important to study also the dump of 183q/32q/8q because it contain a lot of questions that you will not find them in both 149q and tagwa 41q dumps, in my exam none of new questions of 183q/32q/8q came, but I recommended to studied any way Hi guys, I have passed my ccnp routing exam yesterday at () with score (973), actually the dumps of 149q and 41q tagwa is still valid. The command “copy running-config startup-config” will not work so try using this command just skip if it doesn’t work. This configuration is less optimize than the first but it summaries into 2 subnets as the question requires (maybe you will not see this case, don’t worry!). (But please notice that the ip addresses and the subnet masks in your real exam might be different so you might use different ones to solve this question)īut in your real exam, if you see the line “10.0.0.0/8 is a summary,….Null0” then you need to summary using the network 10.0.0.0/8 with the command “ip summary-address eigrp 123 10.0.0.0 255.0.0.0”. Now we jump back to R3 and use the show ip route command to verify the effect, the output is shown below: ![]() In conclusion, we will use the ip summary-address eigrp 123 10.2.0.0 255.255.0.0 at the interface s0/0 of R4 to summary. In the output if we don’t see the summary line (like 10.0.0.0/8 is a summary…) then we should use the command ip summary-address eigrp 123 10.2.0.0 255.255.0.0 so that all the ping can work well. Therefore, to make the routing table of R3 has only 2 subnets we have to summary other subnets into one subnet. We can’t get rid of it in the routing table no matter what technique we use to summary the networks. There is one interesting thing about the output of the show ip route shown above: the 10.2.3.0/24, which is a directly connected network of R3. Use the show ip route command on R3 to view its routing tableīecause we want the routing table of R3 only have 2 subnets so we have to summary sub-networks at the interface which is connected with R3, the s0/0 interface of R4. Next we will configure router R3 so that it has only 2 subnets of 10.0.0.0 network. Notice that the eigrp stub command equals to the eigrp stub connected summary because the connected and summary options are enabled by default. Now R3 will send updates containing its connected and summary routes to other routers. ![]() R3(config-router)# no eigrp stub receive-only Therefore we will remove this command and replace it with the eigrp stub command: This keyword will also prevent any type of route from being sent. The receive-only keyword will restrict the router from sharing any of its routes with any other router in that EIGRP autonomous system. Notice that R3 is configured as a stub receive-only router. Use the show running-config command on router R3 The success of pings from R4 to the R3 LAN interface proves that the fault has been corrected and the R3 IP routing table only contains two 10.0.0.0 subnets.įirst we have to figure out why R3 and R4 can not communicate with each other. You should then configure route summarization only to the distant office router R3 to complete the task after the problem has been solved. Your duty is to find and solve the connectivity failure problem with the remote office router R3. Presently TUT has configured EIGRP on all routers in the network R2, R3, and R4. ![]()
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